i read dont understand
Suppose that
f(2) = −5, g(2) = 3, f ‘(2) = −4, and g'(2) = 1.
Find
h'(2).
a. h(x) = 4f(x) − 3g(x)
h'(2) =
b. h(x) = f(x)g(x)
h'(2) =
c. h(
x) = f(x)/g(x)
d.
h(x) =g(x)/1+f(x)
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